2(4^x+4)+20=32

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Solution for 2(4^x+4)+20=32 equation: 



2(4^x+4)+20=32

We move all terms to the left:

2(4^x+4)+20-(32)=0

We add all the numbers together, and all the variables

2(4^x+4)-12=0

We multiply parentheses

8x+8-12=0

We add all the numbers together, and all the variables

8x-4=0

We move all terms containing x to the left, all other terms to the right

8x=4

x=4/8

x=1/2

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